Water from a tap emerges vertically downwards with an initial speed of 1.0 m s-1. The cross-sectional area of the tap is 10-4 m2. Assume that the pressure is constant throughout the stream of water and that the flow is steady. The cross-sectional area of the stream 0.15 m below the tap is:
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a
5.0×10-4m2
b
1.0 ×10-5m2
c
5.0×10-5m2
d
2.0×10-5m2
answer is C.
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Detailed Solution
Velocity of stream at 0.15 m below the tapu2=u2+2gh =(1)2+2×10×0.15=4 ⇒ u=2 m/s.From equation of continuity A1u1=A2u2 ⇒ A2=A1u1u2=10-412=5×10-5m2.