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Q.

Water from a tap emerges vertically downwards with an initial speed of 1 ms−1 . The cross sectional area of the tap is 10−4m2 . Assume that the pressure is constant throughout the stream of water and that the flow is steady. The cross-sectional area of the stream 0.15m below the tap is

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a

5×10−4m2

b

1×10−5m2

c

5×10−5m2

d

2×10−5m2

answer is C.

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Detailed Solution

Since V2=12+2(g)(0.15) {∵v2−u2=2as} ⇒ v2=4 ⇒ v=2ms−1 Further according to equation of continuity A1u=A2v ⇒ 10−4(1)=A2(2) ⇒ A2=5×10−5m2

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