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Q.

Water from a tap emerges vertically downwards with an initial speed of 5.0 ms−1. The cross-sectional area of tap is 10−4 m2. Assume that the pressure is constant throughout the stream of water and that the flow is steady, the cross- sectional area of stream 3.75 m below the tap is:

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a

5.0×10−4m2

b

1.0×10−4m2

c

5.0×10−3m2

d

2.0×10−5m2

answer is C.

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Detailed Solution

u=5.0ms1,v2=u2+2asv2=(5.0)2+2(10)(3.75)=25+75v=10ms−1A2V=A1u⇒A2=10−4×5.010A2=5.0×10−5m2
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