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Q.

Water from a tap emerges vertically downwards with initial velocity 4 ms−1 . The cross-sectional area of the tap is A. the flow is steady and pressure is constant throughout the stream of water. The distance h  vertically below the tap, where the cross-sectional area of the  stream becomes (23)A,  is (g= 10m/s2 )

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a

0.5 m

b

1 m

c

1.5 m

d

2.2 m

answer is B.

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Detailed Solution

The equation of continuity A1v1=A2v2 A×4=23A×v2 v2=6 ms−1 From Bernoulli’s theorem p+ρg1+12ρv12=p+ρgh2+12ρv22 Or g(h1−h2)=12(v22−v12) g×h=12[(6)2−(4)2] [∵ h1−h2=h] 10×h=12[36−16] h=2020=1 m
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Water from a tap emerges vertically downwards with initial velocity 4 ms−1 . The cross-sectional area of the tap is A. the flow is steady and pressure is constant throughout the stream of water. The distance h  vertically below the tap, where the cross-sectional area of the  stream becomes (23)A,  is (g= 10m/s2 )