Water from a tap emerges vertically downwards with initial velocity 4 ms-1. The cross-sectional area of the tap is A. The flow is steady and pressure is constant throughout the stream of water. The distance h vertically below the tap, where the cross-sectional area of the stream becomes 23A, is g=10m/s2
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a
0.5 m
b
1 m
c
1.5 m
d
2.2 m
answer is B.
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Detailed Solution
The equation of continuity A1v1=A2v2,A×4=23A×v2, From Bernoulli’s theorem P+ρgh1+12ρv12=P+ρgh2+12ρv22 or gh1−h2=12v22−v12g×h=12(6)2−(4)2 ∵h1−h2=h⇒h=1m