First slide

Fluid dynamics

Question

Water is poured in a tank through a cylindrical tube of area of cross-section A and ejecting water at a constant speed 4 m/s. The tank contains a hole of area A/2 at bottom. Level of water in the tank will not go up beyond:
(take g = 10 m/s²)

Easy

A

5.6 m
B

4.8 m
C

3.2 m
D

1.8 m

Solution

For maximum level of water in tank
$A_{1} u_{1} = A_{2} u_{2} A \times 4 = \frac{A}{2} \times \sqrt{2 gh} \Rightarrow h = \frac{64}{2 g} = 3.2 m$

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