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Q.

The water pressure at the bottom of the 11 km deep trench is about 1.1×108Pa. A steel ball of initial volume 0.32m3 is dropped into the ocean and falls to the bottom of the trench. The change in the volume (in m3 ) of the ball when it reaches to the bottom is p×10−4. Find the value of p. [Bulk modulus for steel =1.6×1011N/m2]

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answer is 2.20.

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Detailed Solution

From question, ​P=1.1×108Pa,V=0.32m3,B=1.6×1011Pa​ Change in volume, ​ΔV=PVB=1.1×108×0.321.6×1011=2.2×10−4m3
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