First slide

Surface tension

Question

Water rises to a capillary tube to a height of e cm. If the area of cross section of the tube is one-fourth, the water will rise to a height of

Easy

A

2 cm
B

4 cm
C

8 cm
D

16 cm

Solution

$h = \frac{2 Tcos θ}{ρrg} or h \propto \frac{1}{r}$
When area of cross-section becomes one-fourth, the radius is halved and hence ft is doubled, i.e, 8 cm.

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