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Water rises to a height of 10 cm in a capillary tube, and mercury falls to a depth of 3 . 42 cm in the same capillary tube. If the density of mercury is 13 .6 and the angle of contact is 135o, the ratio of surface tension for water and mercury is

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a

1:0.5

b

1:3

c

1:6.5

d

1.5:1

answer is C.

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Detailed Solution

T=ρrgh2cos⁡θ for water T1=rg×102cos⁡θ=5rg for mercury T2=rg×3⋅42×13⋅62cos⁡135∘=6⋅5×5rg T1T2=16⋅5 or T1:T2=1:6⋅5

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