First slide

Surface tension and surface energy

Question

Water rises up to a height h in a capillary tube of certain diameter. This capillary tube is replaced by a similar tube of half the diameter. Now the water will rise to the height of

Moderate

A

4h
B

3h
C

2h
D

h

Solution

$h \propto \frac{1}{r} \Rightarrow \frac{h_{2}}{h_{1}} = \frac{r_{1}}{r_{2}} = \frac{D_{1}}{D_{2}} = 2 \Rightarrow h_{2} = 2 h_{1}$

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