Water of volume 2 L in a closed container is heated with a coil of 1 kW. While water is heated, the container loses energy at a rate of 160 J/s. In how much time the temperature of water rise from 27°C to 77°C? (Specific heat of water is 4.2 kJ/kg and that of the container is negligible).

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8 min 20 s

6 min 2 s

7 min

14 min

answer is A.

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Detailed Solution

Mass of water is ρ=mvm=ρv=103×2×10−3=2 kg(since 1000 L = 1m3)Now, using ΔQ=msΔT=p−p'×t=2×4.2×10377−27=1000−160t⇒t=2×4.2×103×50840=50060s=8 min 20 s.

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