First slide

Transformer

Question

A 200 watt bulb is connected in secondary coil. Its primary is connected at 400 volt. If efficiency of transformer is 80% and the bulb is running with its peak power then, the current in primary coil is

Moderate

A

$\frac{3}{2} A$
B

$\frac{4}{3} A$
C

$\frac{5}{8}$ A
D

$\frac{1}{2} A$

Solution

$as bulb is glowing with its maximum power the secondary output is 200 watt so primary output will be 200 \frac{100}{80} = 250 W$
$primary current = i_{p} = \frac{P}{V} = \frac{250}{400} = \frac{5}{8} A$

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