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A 200 watt bulb is connected in secondary coil. Its primary is connected at 400 volt. If efficiency of transformer is 80% and the bulb is running with its peak power then, the current in primary coil is

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a
32A
b
43A
c
58 A
d
12A

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detailed solution

Correct option is C

as bulb is glowing with its maximum power the secondary output is 200 watt so primary output will be 20010080= 250 Wprimary current =ip=PV=250400= 58A

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A transformer with efficiency 90% works at 4.5 kW and 100 V. If the secondary voltage is 200 V, then the primary and secondary currents are respectively.


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