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Q.

A 200 watt bulb is connected in secondary coil. Its primary is connected at 400 volt. If efficiency of transformer is 80% and the bulb is running with its peak power then, the current in primary coil is

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a

32A

b

43A

c

58 A

d

12A

answer is C.

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Detailed Solution

as bulb is glowing with its maximum power the secondary output is 200 watt so primary output will be 20010080= 250 Wprimary current =ip=PV=250400= 58A
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