First slide

Transformer

Question

A 200 watt bulb is connected in secondary coil. Its primary is connected at 400 volt. If efficiency of transformer is 80% and the bulb is running with its peak power then, the current in A in primary coil is

Moderate

A

3/2
B

4/3
C

5/8
D

$\frac{1}{2}$

Solution

as bulb is glowing with maximum power 200 W i.e, output power with 80% efficiency input power is $200 \times \frac{100}{80} = 250 W i n p u t c u r r e n t i = \frac{p}{V} = \frac{250}{400} = \frac{5}{8}$

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