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Q.

A 100 watt bulb working on 200 volt and a 200 watt bulb working on 100 volt have:

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a

Resistances in the ratio of 4:1

b

Maximum current ratings in the ratio of 1:4

c

Resistances in the ratio of 2 : 1

d

Maximum current ratings in the ratio of 1:2

answer is B.

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Detailed Solution

R=V2P⇒R1=200×200100=400Ω  and R2=100×100200=50ΩMaximum current rating i=PV So i1=100200 and i2=200100⇒i1i2=14
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