A wave equation which gives the displacement along Y− direction is given byy=10−4sin (60t+2x) where x and y are in metres and t is time in seconds. This represents a wave

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Travelling with a velocity of 30 m/s in the negative x− direction

Of wavelength π metres

Of frequency 30/π Hertz

Of amplitude 10−4 m travelling along the negative x− direction.

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Detailed Solution

y=10−4 sin (60t+2x) =asin(ωt+kx) Now, k=2, 2π/λ=2 or λ=π metre Again. ω=60, or 2πv=60 or v=602π or v=30πHz Again, v=602 m/s=30 m/s

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