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Q.

A wave equation which gives the displacement along Y− direction is given byy=10−4sin  (60t+2x) where x  and y  are in metres and t  is time in seconds. This represents a wave

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a

Travelling with a velocity of 30 m/s in the negative x− direction

b

Of wavelength π  metres

c

Of frequency 30/π  Hertz

d

Of amplitude 10−4 m travelling along the negative x− direction.

answer is Բ.

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Detailed Solution

y=10−4 sin  (60t+2x) =asin(ωt+kx) Now,    k=2,      2π/λ=2   or   λ=π  metre Again.   ω=60,  or 2πv=60   or   v=602π     or  v=30πHz Again,  v=602  m/s=30  m/s
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