Questions
A wave of frequency 500 Hz has velocity 360 m/sec. The distance between two nearest points 60° out of phase, is
a
0.6 cm
b
12 cm
c
60 cm
d
120 cm
detailed solution
Correct option is B
The distance between two points i.e. path difference between them Δ=λ2π×φ=λ2π×π3=λ6=v6n( ∵ v=nλ)⇒Δ=3606×500=0.12 m=12 cmTalk to our academic expert!
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The relation between phase difference () and path difference () is
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