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Q.

A wave of frequency 500 Hz has velocity 360 m/sec. The distance between two nearest points 60° out of phase, is

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a

0.6 cm

b

12 cm

c

60 cm

d

120 cm

answer is B.

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Detailed Solution

The distance between two points i.e. path difference between them Δ=λ2π×φ=λ2π×π3=λ6=v6n( ∵  v=nλ)⇒Δ=3606×500=0.12 m=12 cm
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