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Q.

A wave of frequency 400 Hz  is sent along a string towards a fixed end.  When this wave travels back then after reflection, a node is formed at a minimum distance of 10 cm from the fixed end of the string.  The speed  of the incident wave is

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a

20 cm−1

b

10 cm−1

c

40 cm−1

d

80 cm−1

answer is D.

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Detailed Solution

Given , Frequency n=400 Hz Length l=10 cm l=λ2 λ2=10 λ=20 cm        v=nλ v=400(20)×10−2 v=80 ms−1
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