Q.
The wave number of energy emitted when electron jumps from fourth orbit to second orbit in hydrogen in 20,497 cm-1. The wave number of energy for the same transition in He+ is
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
a
5,099 cm-1
b
20,497 cm-1
c
40,994 cm-1
d
81,988 cm-1
answer is D.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
v¯=1λ=Rz21n12−1n22;∴v¯ α z2∴v¯1v¯2=z1z22;∴20497v¯2=122∴v¯2=81988
Watch 3-min video & get full concept clarity