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The wave number of energy emitted when electron jumps from fourth orbit to second orbit in hydrogen in 20,497 cm-1. The wave number of energy for the same transition in He+ is

a
5,099 cm-1
b
20,497 cm-1
c
40,994 cm-1
d
81,988 cm-1

detailed solution

Correct option is D

v¯=1λ=Rz21n12−1n22;∴v¯ α z2∴v¯1v¯2=z1z22;∴20497v¯2=122∴v¯2=81988

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