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The wavelength of an electron and of a photon of same energy E are related by
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a
λp∝λe
b
λp∝1λe
c
λp∝λe2
d
λp∝λe
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Correct option is C
Wavelength of an electron of energy E isλe=h2meE −−−iWavelength of a photon of same energy E isλp=hcE or E=hcλp −−−iiSquaring both sides of Eq. (i), we getλe2=h22meE or E=h22meλe2 −−−iiiEquating (ii) and (iii), we gethcλp=h22meλe2 λp=2mechλe2 λp∝λe2Similar Questions
An electron is orbiting in 4th energy state in a hydrogen atom. The de-Broglie wavelength associated with this electron is nearly equal to
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