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Q.

The wavelength of 10 keV electron beam is 0.1227 A° When these waves are diffracted from a metal foil having d = 0.55 A°. At angle 𝜃 of first maxima will be present, then what will be the value of sin 𝜃:

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a

0.1116

b

0.2218

c

0.4464

d

0.8928

answer is B.

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Detailed Solution

The wavelength associated with a particle is given byλ=h2mEλ=h2meV=150VÅ for electron M=9.11×10−31kgλ=15010×103=0.122AFor minima,dsinθ=nλFor first minima, n = 10.55sinθ=0.122sinθ=0.1220.55=0.2218
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