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The wavelength of light used in two interference experiments are 600 nm and 800 nm . If the fringe widths are equal when the screens are placed at 4 m and 3 m respectively. The ratio of the distance between the slits is

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a

4 : 3

b

1 : 2

c

2 : 1

d

1 : 1

answer is D.

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Detailed Solution

Wavelength λ 1=600 nm Wavelength λ 2=800 nm Screen distance D1=4 m Screen distance D2=3 m Ratio of distances between the slits d1d2=? d1d2=λ1D1λ2D2 ( ∵ β=λDd ) =600800×43 ∴ d1d2=1:1

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