The wavelength of radiation emitted is when an electron jumps from the third to the second orbit of hydrogen atom. For the electron jump from the fourth to the second orbit of the hydrogen atom, the wavelength of radiation emitted will be
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a
1625λ0
b
2027λ0
c
2720λ0
d
2516λ0
answer is B.
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Detailed Solution
1λ=R 1n12-1n22⇒1λ3→2=R 1(2)2-1(3)2=5R36 and 1λ4→2=R1(2)2-1(4)2=3R16 ∴λ4→2λ3→2=2027⇒λ4→2=2027λ0