Q.
The wavelengths of the first line in Balmer series in hydrogen spectrum is λ What is the wavelength of second line
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a
2027λ
b
2720λ
c
536λ
d
365λ
answer is A.
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Detailed Solution
For first line of Balmer series, we have 1λ1=R14−19=5R36 For second line of Balmer series 1λ2=R14−116=3R16 λ2λ1=16×53×36=2027 or λ2=2027λ
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