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Q.

The wavelengths of the first line in Balmer series in hydrogen spectrum is λ What is the wavelength of second line

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a

2027λ

b

2720λ

c

536λ

d

365λ

answer is A.

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Detailed Solution

For first line of Balmer series, we have 1λ1=R14−19=5R36 For second line of Balmer series 1λ2=R14−116=3R16 λ2λ1=16×53×36=2027  or  λ2=2027λ
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