We have a galvanometer of resistance 25 Ω It is shunted by a 2.5 Ω wire. The part of total current that flows through the galvanometer is given as
igi = 111
igi = 110
igi = 311
igi = 411
iig = G+SS ⇒igi =SG+S = 2.527.5 = 111