Questions
We have a galvanometer of resistance It is shunted by a wire. The part of total current that flows through the galvanometer is given as
detailed solution
Correct option is A
iig = G+SS ⇒igi =SG+S = 2.527.5 = 111Talk to our academic expert!
Similar Questions
A moving coil galvanometer converted into an ammeter reads up to 0.03 A by connecting a shunt of resistance 4r across it and ammeter reads up to 0.06 A, when a shunt of resistance r is used. What is the maximum current which can be sent through this galvanometer if no shunt is used?
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