We have two (narrow) capillary tubes $$T1$$ and $$T2$$. Their lengths are $$l1$$ and $$l2$$ and radii of $$cross-section$$ are $$r1$$ and $$r2$$ respectively. The rate of flow of water under a pressure difference P through tube $$T1$$ is $$8cm3/$$$$sec$$. If $$l1$$ $$=$$ $$2l2$$ and $$r1$$ $$=r2$$, what will be the rate of flow when the two tubes are connected in series and pressure difference across the combination is same as before $$(=$$ $$P)$$

Question

Infinity Learn · Accepted Answer

$$V=$$π$$Pr48$$η$$l=8cm3secFor$$ composite tube $$V1=P$$$$π$$$$r48$$η$$l+l2=23$$$$π$$$$Pr48$$η$$l=23$$×$$8=163cm3sec$$∵$$l1=l=2l2$$ or $$l2=l2$$

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