A wedge of mass m is pushed with a speed v0 on a rough horizontal plane. The angle of friction between the wedge and horizontal plane is ϕ. The angle of inclination θ of the pendulum is
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a
ϕ
b
90∘−ϕ
c
tan−1mMtanϕ
d
None of these
answer is A.
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Detailed Solution
Since frictional force acts on the block, its deceleration is μg. So in the frame of wedge, a pseudo force μmg acts on the block and it is inclined at angle θ=ϕ with vertical.
A wedge of mass m is pushed with a speed v0 on a rough horizontal plane. The angle of friction between the wedge and horizontal plane is ϕ. The angle of inclination θ of the pendulum is