A wedge Q of mass M is placed on a horizontal frictionless surface AB and a block P of mass m is released on its frictionless slope. As P slides by a length L on this slope of inclination θ, Q would slide by a distance of
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
(mM)L cosθ
b
mL(M+m)
c
(M+m)(mL cos θ)
d
(mL cos θ)(m+M)
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Let Q slides by a distance r towards left, then net horizontal displacement of P w.r.t. ground= L cos θ-xNow apply m1x1 = m2x2 ⇒Mx = m(L cosθ-x)⇒x = mL cosθM+m