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Questions  

Weight of a body at a height R/2 (Radius of earth = R) above the surface of earth is 80 N. What will be its weight at a depth R/2 below te surface of earth?

a
75 N
b
25 N
c
90 N
d
120 N

detailed solution

Correct option is C

W1=mg1=mGMr12W2=mg2=m.gsr2R=mGMR3r2∴ W2W1=r2R3×r12=R2×(R+R2)2R3=98⇒W2=80×98N=90N

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