Weight of a body of mass m decreases by 1% when it is raised to height h above the earth’s surface. If the body is taken to a depth h in a mine, change in its weight is

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2% decrease

0.5% decrease

1% increase

0.5% increase

answer is B.

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Detailed Solution

For height Δgg×100%=2hR=1%;For depth Δgg×100%=dR=hR=12%=0.5%

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