Weight of a body on the surface of earth is 100 N. If R be the radius of earth, then what will be the weight of the body at a height R/2 above the surface of earth?
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a
50
b
25 N
c
44.45 N
d
64.25 N
answer is C.
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Detailed Solution
W=mg=GMmR2 (on the surface of earth) At a height h, W1=mg1=GMmR+h2∴ W1W=RR+h2=RR+R22=49⇒W1=49×100 N=44.45 N