A weight of 200 kg is suspended by vertical wire of length 600.5 cm. The area of cross-section of wire is 1 mm2. When the load is removed, the wire contracts by 0.5 cm. The Young's modulus of the material of wire will be

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2.35×1012 N/m2

1.35×1010 N/m2

13.5×1011 N/m2

23.5×109 N/m2

answer is A.

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Detailed Solution

F=2000N,L=6m,l=0.5cm,A=10−6m2Y=FLAl=2000×610−6×0.5×10−2=2.35×1012N/m2

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