First slide

Vectors

Question

Weight mg of a block is a force acting downward towards centre of the earth. A block of mass 1 kg is placed on an inclined plane as shown in the figure. Find the x-component and y-component of weight of the block are

Easy

A

6 N, -8 N
B

6 N, 8 N
C

8 N, 6 N
D

8 N, -6 N

Solution

mg = $1 \times 10 = 10 N$
From figure, the x-component is
$mg \sin 37^{0} = 1 \times 10 \times \frac{3}{5} = 6 N$
and y-component is
$- mg \cos 37^{0} = - 1 \times 10 \times \frac{4}{5} = - 8 N$

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