Question

The weight of an object is 90 kg at the surface of the earth. If it is taken to a height equal to half of the radius of the earth, then its weight will become [MPPET 2013]

Moderate

Solution

Weight of the object at height h above the surface of the
earth, $w^{'} = \frac{w}{{(1 + \frac{h}{R})}^{2}} \Rightarrow w^{'} (h = R / 2) = \frac{w}{(1 + 1 / 2)^{2}}$
$\Rightarrow w^{'} = w \times \frac{4}{9} = 90 \times \frac{4}{9} = 40 kg$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

SCAN ME