A weight suspended from the free end of a vertically hanging spring produces an extension of 3cm. The spring is cut into two parts so that the length of the longer part is 23 of the original length, If the same weight is now suspended from the longer part of the spring, the extension produced will be
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a
0.1 cm
b
0.5 cm
c
1 cm
d
2 cm
answer is D.
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Detailed Solution
Initially , 3k=mg or k=mg3 New force constant of longer partk1=32k=32×mg3=mg2 Finally, k'y=mg y=mgk'=mgmg×2=2cm