A weightless spring which has a force constant fr oscillates with frequency f when a mass m is suspended from it. The spring is cut into two halves and a mass 2 m is suspended from one of the halves. The frequency of oscillation will now be:
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a
f
b
2f
c
f/212
d
f×212
answer is A.
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Detailed Solution
Spring constant of each halves = 2 kf'=2π2k2m=2πkm=f