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Q.

A weightless spring which has a force constant oscillates with frequency n when a mass m is suspended from it. The spring is cut into two equal halves and a mass 2m is suspended from it. The frequency of oscillation will now become

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a

n

b

2n

c

n/2

d

n(2)1/2

answer is A.

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Detailed Solution

n=12πkm⇒nn'=km×m'K'=km×2m2K=1⇒n'=n
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