At what angle should a ball be thrown with a speed of 56ms−1 such that it covers the maximum possible range without hitting the 40 m high ceiling of the hall?

Here, u=56ms−1Let θ be the angle of projection with the horizontal to have maximum range, with maximum height = 40 mMaximum height, H=u2sin2⁡θ2g40=(50)2sin2⁡θ2×9.8sin2⁡θ=2×9.8×40(56)2=14 or sin⁡θ=12 or θ=sin−1⁡12=30∘