Question

At what angle with the horizontal should a ball be thrown so that its range R is related to the time of flight as R = 5T²: (Take g = 10ms^-2)

Moderate

Solution

$\frac{R}{T^{2}} = g \frac{\sin 2 θ}{4 \sin^{2} θ} = \frac{g}{2} \cot θ = 5 \cot θ Given : \frac{R}{T^{2}} = 5, hence, 5 = 5 \cot θ or θ = 45^{\circ} .$

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