First slide

Projection Under uniform Acceleration

Question

At what angle with the horizontal should a ball be thrown so that the range R is related to the time of flight as $R = 5 T^{2} ?$ (Take g= 10 ms-²)

Easy

A

30^o
B

45^o
C

60^o
D

90^o

Solution

$\frac{R}{T^{2}} = g \frac{\sin 2 θ}{4 \sin^{2} θ} = \frac{g}{2} cotθ = 5 cotθ Given \frac{R}{T^{2}} = 5 Hence, 5 = 5 \cot θ or θ = 45 °$

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