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Questions  

 At what angle with the horizontal should a ball be thrown so that the range R is related to the time of flight as R = 5T2? (Take g= 10 ms-2)

a
30°
b
45°
c
60°
d
90°

detailed solution

Correct option is B

RT2=gsin2θ4sin2θ=g2cotθ=5cotθGiven RT2=5, Hence, 5 = 5 cot θ or θ = 45°

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Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.

Reason : Range of projectile does not depend on the initial velocity of a body.


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