First slide

Projection Under uniform Acceleration

Question

At what angle with the horizontal should a ball be thrown so that the range R is related to the time of flight as R = 5 $T^{2}$ ? (Take g= 10 m $s^{- 2}$ )

Moderate

A

30°
B

45°
C

60°
D

90°

Solution

$\frac{R}{T^{2}} = g \frac{\sin 2 θ}{4 \sin^{2} θ} = \frac{g}{2} \cot θ = 5 \cot θ$
Given $\frac{R}{T^{2}}$ =5, Hence, 5 = 5 cot $θ$ or $θ$ = 45°

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