Q.
What is the angular momentum of an electron in Bohr's hydrogen atom whose energy is -0.544 eV?
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a
hπ
b
2hπ
c
5h2π
d
7h2π
answer is C.
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Detailed Solution
By using E=−13.6n2eV for H2 atom⇒−0.544=−13.6n2⇒n2=25⇒n=5∴Angular momentum =nh2π=5h2π.