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Questions  

What is the change in potential energy ( in calories) of a 10 kg mass after 41.8m of fall?

a
1000 cal
b
800 cal
c
1500 cal
d
2000 cal

detailed solution

Correct option is A

Change in potential energy =  ΔU=mgh=10×10×41.8=4180J If mechanical energy in joule produces the same temperature change as heat, we write, W=JH, H=ΔUJ=41804.18 =1000 cal

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