What is the change in potential energy ( in calories) of a 10 kg mass after 41.8m of fall?
1000 cal
800 cal
1500 cal
2000 cal
Change in potential energy = ΔU=mgh=10×10×41.8=4180J If mechanical energy in joule produces the same temperature change as heat, we write, W=JH, H=ΔUJ=41804.18 =1000 cal