Questions  

What is the depth at which the value of acceleration due to gravity becomes 1/ n times the value that the 
surface of earth? (Radius of earth =R)  [NEET 2020] 

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By Expert Faculty of Sri Chaitanya
a
R/n2
b
R(n-1)/n
c
Rn /(n-1)
d
R/n
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detailed solution

Correct option is B

Radius of earth = RLet at depth d, acceleration due to gravity be gd which becomes gn.i.e.,             gd=gn⇒g1-dR=gn⇒  1-dR=1n⇒1-1n=dR⇒  n-1n=dR⇒d=n-1nR

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