What is the depth at which the value of acceleration due to gravity becomes 1/ n times the value that the surface of earth? (Radius of earth =R) [NEET 2020]

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R/n2

R(n-1)/n

Rn /(n-1)

R/n

answer is B.

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Detailed Solution

Radius of earth = RLet at depth d, acceleration due to gravity be gd which becomes gn.i.e., gd=gn⇒g1-dR=gn⇒ 1-dR=1n⇒1-1n=dR⇒ n-1n=dR⇒d=n-1nR

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