Questions
What is the depth at which the value of acceleration due to gravity becomes 1/ n times the value that the
surface of earth? (Radius of earth =R) [NEET 2020]
detailed solution
Correct option is B
Radius of earth = RLet at depth d, acceleration due to gravity be gd which becomes gn.i.e., gd=gn⇒g1-dR=gn⇒ 1-dR=1n⇒1-1n=dR⇒ n-1n=dR⇒d=n-1nRTalk to our academic expert!
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