Q.
What is the dimensions of energy in terms' of linear momentum [p], area [A] and time [T]?
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a
[p1A1T1]
b
[p2A2T-1]
c
[p1A½T-1]
d
[p½A½T-1]
answer is C.
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Detailed Solution
Dimensions of energy in terms of linear momentum (p), area (A) and time (T), is related to E = paAbyc ... (i)Writing dimensional formula of both sides, we get [ML2T-2] = [MLT-1]a [L2]b[T]c [ML2T-2] = [MaLa + 2b T-a +c]Comparing the exponents, a = 1, a + 2b = 2 2b = 1⇒ b = 12 - a + c = -2⇒ -1 + c = -2⇒ c = -l∴ From Eq. (i), we have⇒ E = [pA½T-1]
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