First slide

Simple hormonic motion

Question

At what displacement is the KE of a particle performing SHM of amplitude 10cm is three times its PE ?

Easy

A

2.5 cm
B

5 cm
C

7.5 cm
D

10 cm

Solution

K.E. = 3.P.E
$P.E. = \frac{1}{2} {mω}^{2} x^{2}; K . E . = \frac{1}{2} {mω}^{2} (A^{2} - x^{2})$

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