At what displacement is the kinetic energy of a particle performing simple harmonic motion of amplitude 10 cm is three times it’s potential energy?

KE=3(PE)we know,Kinetic energy KE, Potential energy PE as    KE=12mω2A2-x2    PE=12mω2x2 by the question, KE = 3 PE       ⇒12mω2A2-x2=32mω2x2   on simplification, A2=4x2                                ⇒x=A/2     Given A=10 cm    ∴x=102=5cm