What increase in pressure is required to decrease the volume of 200 litre of water by 0.004 percent? Given bulk modulus of water is 2100 MPa.
21 kPa
84 kPa
42 kPa
none of these
∆V = 0.00004(200 L) = 0.008 L
∆p = B(-∆VV)
= (2100 MPa)(0.008 L200 L)
= 0.084 MPa = 84 kPa