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What is the lowest frequency of light (in x 1014 Hz) that will cause the emission of photoelectrons from the surface of a metal (for which work function is 1.65 eV)?

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answer is 4.

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Detailed Solution

Minimum frequency: W0=hv0⇒ v0=W0h=1.65×1.6×10−196.6×10−34=4×1014Hz
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What is the lowest frequency of light (in x 1014 Hz) that will cause the emission of photoelectrons from the surface of a metal (for which work function is 1.65 eV)?