First slide

Photoelectric effect and study of photoelectric effect

Question

What is the lowest frequency of light (in x 10¹⁴ Hz) that will cause the emission of photoelectrons from the surface of a metal (for which work function is 1.65 eV)?

Moderate

Solution

$\begin{array}{l} Minimum frequency: W_{0} = h v_{0} \\ \Rightarrow v_{0} = \frac{W_{0}}{h} = \frac{1.65 \times 1.6 \times 10^{- 19}}{6.6 \times 10^{- 34}} = 4 \times 10^{14} Hz \end{array}$

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