First slide

Friction as component of Net Contact Force

Question

What is the maximum value of the force F such that the block shown in the arrangement, does not move

Easy

A

20 N
B

10 N
C

12 N
D

20/3 N

Solution

$f = μR$
$Fcos 60 ° = μ (W + Fsin 60 °)$
$Substituting μ = \frac{1}{4 \sqrt{3}} & W = 10 \sqrt{3} We get F = \frac{20}{3} N$

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