What is the net force on the square coil?

Force on side BC and AD are equal but opposite, so their resultant will be zero. But   FAB= 10−7 × 2 × 2 × 12 × 10−2×15 × 10−2 = 3 × 10−6Nand   FCD= 10−7 × 2 × 2 × 112 × 10−2×15 × 10−2 = 0.5 × 10−6N⇒ Fnet =FAB−FCD =2.5 × 10−6N= 25 × 10−7N  towards  the  wire