Questions
What is the net force on the square coil?
a
25 × 10−7 N moving towards wire
b
25 × 10−7 N moving away from wire
c
35 × 10−7 N moving towards wire
d
35 × 10−7 N moving away from wire
detailed solution
Correct option is A
Force on side BC and AD are equal but opposite, so their resultant will be zero. But FAB= 10−7 × 2 × 2 × 12 × 10−2×15 × 10−2 = 3 × 10−6Nand FCD= 10−7 × 2 × 2 × 112 × 10−2×15 × 10−2 = 0.5 × 10−6N⇒ Fnet =FAB−FCD =2.5 × 10−6N= 25 × 10−7N towards the wireTalk to our academic expert!
Similar Questions
Two thin long parallel wires separated by a distance b carrying a current i ampere each. The magnitude of the force per unit length exerted by one wire on the other is
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